Thread: Internet will run out of addresses in two years.

Originally Posted by Kovich

And then eventually that, too, will run out and we'll have to devise another solution.

We constantly seek short-term solutions. Instead of finding something that will be suitable for now, we should find something that will always be suitable.

With IPv6 there's 1000 IP addresses for each person in the world, so I don't expect any problems for more than 1000 years.

Originally Posted by Shenron

With IPv6 there's 1000 IP addresses for each person in the world, so I don't expect any problems for more than 1000 years.

Sounds like a pretty long-term solution to me

That's what they said the first time. :P

Originally Posted by Kovich

That's what they said the first time. :P

Not really, IPV4 doesn't even cover the current World's population, on the other hand IPV6 covers the entire population * 1000 (actually a lot more than that).

Basically this means that, on average, you can have an IP address for each of your own properties (from pencils to shoes ).

could someone explain in simple terms what this IPV6 IP address thing has to do with stopping domain name combinations from running out in 2 years?

1,000 IPs x 6,795,253,544 People = 6.79525354 × 10^12

4.4 humans born per second. 264 per minute.

(6.79525354 × (10^12)) / 264 = 2.57395967 × 10^10

Therefore, we can see that it will be 2.57395967 × 10^10 minutes until all of those are used up. Assuming we're not countering the number with deaths or altering the rate of birth.

Let's counter the number with deaths:
1.8 die every second. 108 each minute.

264 minus 108 = 156. (6.79525354 × (10^12)) / 156 = 4.35593176 × 10^10

My conclusion:
Come and see me in 4.35593176 × 10^10 minutes, Shenron. (Approximately 82,875.414 years.)

Originally Posted by Kovich

1,000 IPs x 6,795,253,544 People = 6.79525354 × 10^12

4.4 humans born per second. 264 per minute.

(6.79525354 × (10^12)) / 264 = 2.57395967 × 10^10

Therefore, we can see that it will be 2.57395967 × 10^10 minutes until all of those are used up. Assuming we're not countering the number with deaths or altering the rate of birth.

Let's counter the number with deaths:
1.8 die every second. 108 each minute.

264 minus 108 = 156. (6.79525354 × (10^12)) / 156 = 4.35593176 × 10^10

My conclusion:
Come and see me in 4.35593176 × 10^10 minutes, Shenron. (Approximately 82,875.414 years.)

gotta say, that was ubergeek!!

Originally Posted by Kovich

1,000 IPs x 6,795,253,544 People = 6.79525354 × 10^12

4.4 humans born per second. 264 per minute.

(6.79525354 × (10^12)) / 264 = 2.57395967 × 10^10

Therefore, we can see that it will be 2.57395967 × 10^10 minutes until all of those are used up. Assuming we're not countering the number with deaths or altering the rate of birth.

Let's counter the number with deaths:
1.8 die every second. 108 each minute.

264 minus 108 = 156. (6.79525354 × (10^12)) / 156 = 4.35593176 × 10^10

My conclusion:
Come and see me in 4.35593176 × 10^10 minutes, Shenron. (Approximately 82,875.414 years.)

LOL, great post!
It looks like I might assign an IP address to each of my fishes.

Originally Posted by Kovich

1,000 IPs x 6,795,253,544 People = 6.79525354 × 10^12

4.4 humans born per second. 264 per minute.

(6.79525354 × (10^12)) / 264 = 2.57395967 × 10^10

Therefore, we can see that it will be 2.57395967 × 10^10 minutes until all of those are used up. Assuming we're not countering the number with deaths or altering the rate of birth.

Let's counter the number with deaths:
1.8 die every second. 108 each minute.

264 minus 108 = 156. (6.79525354 × (10^12)) / 156 = 4.35593176 × 10^10

My conclusion:
Come and see me in 4.35593176 × 10^10 minutes, Shenron. (Approximately 82,875.414 years.)

Cool stuff

atleast we know one thing..IPv8 has no chance till the next 82k years..

Right. But my point was - why not just implement something like IPv8 now?

I mean, why do we intentionally limit ourselves?